A spiral spring is compressed by 0.03m. Calculate the energy stored in the spring if its force constant is 300N/ m
11 answers
(1/2)(300)(.03)^2 Joules
Anser
0.135j
Pls what is the answer
0.135
e=0.03m. w=? k=300N/m. w=1/2ke^2. 1/2×300×(0.03^2). 150 × 0.0009. = 0.135 J
The elastic or force constant is 300;extension=0.03 P.E=1/2(ke)2
=0.5*300(0.03)2
=150*0.0009
=0.135joules
i hope you get this
it is simple
good luck.
=0.5*300(0.03)2
=150*0.0009
=0.135joules
i hope you get this
it is simple
good luck.
Thank u i m ok
0.135j
0.135J
Yes, that is correct.
4 answers