2 cosy+siny =?

Write the equation siny=x in the form of an inverse function. Answer: x=Sin^-1y Thanks

Prove that (cosy/1+siny) + (1+siny/cosy) = 2secy

sinx+ siny/ (cosx+cosy)= tan 1/2 (x+y) prove this identity

3+siny = 3cos^2 y for 0<Y<360

range of sin(siny) +cos(siny)

(Cosx)^y=x^siny find dy/dx at point pi/(4,0)

cosx+cosy=a and sinx+siny=b show that sin2x+sin2y=2ab(1-(2/(a^2+b^2)) plz plz show step

If sin2x=7/25, siny=-2/sq root of 13, cot y>0, and -pi/4<x<pi/4, find sin(2y-a)

f(x,y)=sinx+siny+sin(x+y), 0<=x<=2π 0<=y<=2π Find the extrema of f and state their nature show s...

ifcosX+cosY=a and sinX+sinY=b than prove thatsin2X+sin2Y=2ab(1-2/(a^2+b^2)

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