Question
ifcosX+cosY=a and sinX+sinY=b than prove thatsin2X+sin2Y=2ab(1-2/(a^2+b^2)
Answers
ab = sinx cosx + sinx cosy + cosx siny + siny cosy
= sin(x+y) + sinx cosx + siny cosy
using your sum/difference formulas,
= sin(x+y) + 1/2 sin2x + 1/2 sin2y
= sin(x+y) + sin(x+y)cos(x-y)
= sin(x+y)(1+cos(x-y))
a^2+b^2 = cos^2x + 2cosx cosy + cos^2y + sin^2x + 2sinx siny + sin^2y
= 2+2cos(x-y)
2/(a^2+b^2) = 1/(1+cos(x-y))
1-2/(a^2+b^2) = cos(x-y)/(1+cos(x-y))
so, using your sum/difference formulas as above,
2ab(1-2/(a^2+b^2)) = 2sin(x+y)cos(x-y)
= sin2x + sin2y
*whew*
= sin(x+y) + sinx cosx + siny cosy
using your sum/difference formulas,
= sin(x+y) + 1/2 sin2x + 1/2 sin2y
= sin(x+y) + sin(x+y)cos(x-y)
= sin(x+y)(1+cos(x-y))
a^2+b^2 = cos^2x + 2cosx cosy + cos^2y + sin^2x + 2sinx siny + sin^2y
= 2+2cos(x-y)
2/(a^2+b^2) = 1/(1+cos(x-y))
1-2/(a^2+b^2) = cos(x-y)/(1+cos(x-y))
so, using your sum/difference formulas as above,
2ab(1-2/(a^2+b^2)) = 2sin(x+y)cos(x-y)
= sin2x + sin2y
*whew*
not well
not well this problem
cosx+cosy=a sinx+siny=b find tha value of sin2x+sin2y=?
2+3
Related Questions
Ok, i've tried this question, and it brings me to no answers. Please help!
Prove the following:...
sinx+ siny/ (cosx+cosy)= tan 1/2 (x+y)
prove this identity
How do I get (sinx cosy + cosx siny) (cosx cosy + sinx siny) in the form of 1/2(sin2x + sin2y)?
cosx+cosy=a and sinx+siny=b show that sin2x+sin2y=2ab(1-(2/(a^2+b^2))
plz plz show step