Asked by jimson
A cannon shell is fired straight up from the ground at an initial speed of 225 m/s. After how much time is the shell at a height of 6.20 x 102 m above the ground and moving downward? (a) 2.96 s (b) 17.3 s (c) 25.4 s (d) 33.6 s (e) 43.0 s
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5
Answers
Answered by
R_scott
620 = -4.9 t^2 + 225 t
0 = -4.9 t^2 + 225 t - 620
solve with quadratic formula
... you want the largest solution (on the way down)
0 = -4.9 t^2 + 225 t - 620
solve with quadratic formula
... you want the largest solution (on the way down)
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