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The equation for a normal calibration curve for the detection of iron(II) is determined experimentally to be 𝐴 = 12.93 𝑀−1 [𝐹𝑒...Asked by Rafaela
The equation for a normal calibration curve for the detection of
iron(II) is determined experimentally to be
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
Analysis of a sample with unknown concentration gives an
absorbance reading of 0.106. What is the concentration of iron(II) in
the unknown?
iron(II) is determined experimentally to be
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
Analysis of a sample with unknown concentration gives an
absorbance reading of 0.106. What is the concentration of iron(II) in
the unknown?
Answers
Answered by
DrBob222
Plug in the numbers and solve the equation.
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
0.106 = 12.93(Fe^2+) + 0.0017
Solve for (Fe^2+) = ?
𝐴 = 12.93 𝑀^−1 [𝐹𝑒^2+] + 0.0017
0.106 = 12.93(Fe^2+) + 0.0017
Solve for (Fe^2+) = ?
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