Asked by Raphael
Find the equation of the normal to the curve y=x^2-x-2 at the point where the curve meet the line y=x+1
Answers
Answered by
oobleck
The curves meet at (-1,0) and (3,4)
y' = 2x-1
at (-1,0) y' = -1
so the normal has a slope of 1
That makes the equation of the normal
y-0 = 1(x+1)
Now do the other point in like wise
y' = 2x-1
at (-1,0) y' = -1
so the normal has a slope of 1
That makes the equation of the normal
y-0 = 1(x+1)
Now do the other point in like wise
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