Asked by help
an equation of the normal to the graph of f(x)= x/(2x-3) at (1,f(1)
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Answered by
bobpursley
find the slope of f(x), or
f'= d/dx (f(x)) at the point.
Then, the slope to the normal is the negative reciprocal of that value.
f'= d/dx (f(x)) at the point.
Then, the slope to the normal is the negative reciprocal of that value.
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