Find the equation of the normal to the curve f(x) = 3cos(2x) at the point x = 0.

In class, we learnt to find the derivate of the function, which would represent the slope.
After I did that, I found the slope to be 0.. but that is not what my graphing calculator tells me.. So, I'm not too sure where I went wrong :S

Similar Questions

A curve has implicit equation x^2-2xy+4y^2=12a)find the expression for dy/dx in terms of y and x. hence determine the
1. 1 answer
. Given that x²cos y_sin y=0,(0,π).A. Verify that the given points on the curve. B.use implicit differention to find the slope
1. 1 answer
Given that x²cos y-sin y=0 ,(0,π):a)verfiy that given point is on the curve. b)use implicit differentiation to find the slope
1. 1 answer
1. Consider the curve y=x^2.a. write down (dy)/(dx) My answer: 2x The point P(3,9) lies on the curve y=x^2. b. Find the gradient
1. 2 answers