Asked by Anonymous

a uniform half metre rule is freely pivoted at the 20 cm mark and its balance horizontaly when a body of mass 30g is hung 5cm mark from end calculate the mass of rule
Answered by Damon
the 30g mass is 20-5 = 15 cm left of pivot
the ruler mass m is 50-20 = 30 cm right of pivot
so
30 g * 15 cm = m * 30
m = 15 grams
Answered by Radolly
m=15g
Answered by Nyangige
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Answered by Pretty
15 grams
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