Question

A uniform half metre rule is freely pivoted at the 20cm mark and it balances horizontally when a weight of 10N is suspended at 4cm mark, calculate weight of the meter rule and the reaction of the knife
down
10 N at (20-4) = 16 cm left from pivot
m g N at (50-20) = 30 cm right of pivot
so 10 *16 = mg * 30
mg = 16/3 = 5.33 Newtons
force up = 10 + 5.33 Newtons

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