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A solid rectangular block measures 0.100m x 0.080m x 0.060m and float freely in a liquid of density 13546kg/m³. If the depth of liquid is 0.045m up the block largest side find the density of the block...
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Answered by
Damon
find the volume of the block V = 0.100m * 0.080m * 0.060m
then its mass is Rho * V
find the mass of liquid displaced M = 13546 * 0.100m * 0.080m * 0.045m
which Archimedes says is the mass of the block.
then Rho = M/V
then its mass is Rho * V
find the mass of liquid displaced M = 13546 * 0.100m * 0.080m * 0.045m
which Archimedes says is the mass of the block.
then Rho = M/V
Answered by
Same-check my answer
Sir Damon I got
Answer=10,159.5?
Answer=10,159.5?
Answered by
Damon
Yes
Answered by
Same
Hurray
Answered by
Faith
I still can't get my answer
Answered by
Faith
Hurray my problem has been solved i got my answer
Answered by
Faith
10,159.5
Answered by
Mary
10159.5
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