Question

A solid rectangular block measures 0.100m x 0.080m x 0.060m and float freely in a liquid of density 13546kg/m³. If the depth of liquid is 0.045m up the block largest side find the density of the block...

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find the volume of the block V = 0.100m * 0.080m * 0.060m
then its mass is Rho * V

find the mass of liquid displaced M = 13546 * 0.100m * 0.080m * 0.045m
which Archimedes says is the mass of the block.
then Rho = M/V
Sir Damon I got

Answer=10,159.5?
Yes
Hurray
I still can't get my answer
Hurray my problem has been solved i got my answer
10,159.5
10159.5

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