Suppose we had
∫ (2 + 3x)^5 dx
wouldn't that just be (1/5)(1/3)(2+3x)^6 + c ??
so ∫ (p-qt)^n dt = (1/n)(-1/q)(p - qt)^(n+1) + C
Integrate the equation (p-qt)^n with respect to t
3 answers
1/(n+1) ...
Yup, thanks oobleck for checking me
(1/(n+1) )(-1/q)(p - qt)^(n+1) + C
(1/(n+1) )(-1/q)(p - qt)^(n+1) + C