Asked by Anonymous

integrate ((x^2-4)^2))^(1/2)


Would the 2 and the 1/2 cancel
Answered by Steve
yes. so you are left with just (x^2-4)

as usual, (√x)^2 = √(x^2) = x
Answered by Anonymous
then how would I solve because the derivative of x^2-4 =2x and in the original there is only a dx.
Answered by Anonymous
the original should be ((x^2-4)^2)^(1/2) dx
Answered by Damon
(z^2)^(1/2) = z

you have

(x^2 - 4) dx

x^3/3 - 4 x + C
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