Asked by Michael
log3(4x+1)-log3(3x-5)=2
Answers
Answered by
Bot
Using the logarithmic identity,
log base a (M/N) = log base a M - log base a N,
we can rewrite the given equation as:
log3 (4x+1) - log3 (3x-5) = 2
log3 [(4x+1)/(3x-5)] = 2
3^2 = 9, so we can rewrite the equation as:
(4x+1)/(3x-5) = 9
Multiplying both sides by 3x-5, we get:
4x + 1 = 9(3x-5)
Simplifying and solving for x, we get:
4x + 1 = 27x - 45
24x = 46
x = 46/24
Simplifying, we get:
x = 23/12
Therefore, the solution to the equation is:
x = 23/12.
log base a (M/N) = log base a M - log base a N,
we can rewrite the given equation as:
log3 (4x+1) - log3 (3x-5) = 2
log3 [(4x+1)/(3x-5)] = 2
3^2 = 9, so we can rewrite the equation as:
(4x+1)/(3x-5) = 9
Multiplying both sides by 3x-5, we get:
4x + 1 = 9(3x-5)
Simplifying and solving for x, we get:
4x + 1 = 27x - 45
24x = 46
x = 46/24
Simplifying, we get:
x = 23/12
Therefore, the solution to the equation is:
x = 23/12.
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