Asked by David
Log3(x2+2x+2)=0 what is the answer?
Answers
Answered by
Anonymous
if log3 (a) = 0
then
3^[log3(a)]= a = 3^0 = 1
so
x^2 + 2 x + 2 = 1
x^2 + 2 x + 1 = 0
(x+1)(x+1) = 0
x = -1
then
3^[log3(a)]= a = 3^0 = 1
so
x^2 + 2 x + 2 = 1
x^2 + 2 x + 1 = 0
(x+1)(x+1) = 0
x = -1
Answered by
Mary Daniel moses
X^2+2x+2=1
X^2+2x+1=0
(X+1)(x+1)=0
X=-1
X^2+2x+1=0
(X+1)(x+1)=0
X=-1
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