Asked by Abraham
A uniform rod 1.8m long and of mass 10kg rest horizontally on support at its ends. If a weight of mass 3kg is attached at a point 1.2m from one end, find the reactions from the support
Answers
Answered by
Damon
F1 + F2 = 10 g + 3 g = 13 g
0.9 (10 g) + 1.2 (3 g) = 1.8 (F2)
so
1.8 F2 = 9 g + 3.6 g = 12.6 g
F2 = 7 g Newtons
F1 = 13 g - 7 g = 6 g Newtons
g is gravitational acceleration about 9.81 m/s^2 on earth
0.9 (10 g) + 1.2 (3 g) = 1.8 (F2)
so
1.8 F2 = 9 g + 3.6 g = 12.6 g
F2 = 7 g Newtons
F1 = 13 g - 7 g = 6 g Newtons
g is gravitational acceleration about 9.81 m/s^2 on earth
Answered by
Ackah
A uniform rod 1.8m long am of mass10kg rest horizontal on support at it ends.If weight of mass 3kg is attached at a point 1.2m from one ends find reaction from the support
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