Asked by shiva
1. A Uniform rod AB 3m long weighing 3 Kg is held horizontally by two strong vertical strings at its ends. A weight of 7 kg is hanging on the rod at a distance of 1m from end A and another weight of 12 Kg is hanging at 0.5 m from end B.(a)Make the free body diagram of the rod and (b)Find the tension in two strings.
Answers
Answered by
bobpursley
you know the tension sum is equal to the weights.
Ta+Tb-3*g-12*g-7g=0 where g is 9.8N/kg
Then, sum moments about any point. I will sum at end a.
1.5*3g -Tb*3+1*7*g+2.5*12g=0
Ta+Tb-3*g-12*g-7g=0 where g is 9.8N/kg
Then, sum moments about any point. I will sum at end a.
1.5*3g -Tb*3+1*7*g+2.5*12g=0
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