Question
Two airplanes leave an airport at the same time, flying in the same direction. One of the plane is flying at twice the speed of the other. If after 4 hours they are 1800 km apart find the speed of each plane.
Answers
distance = speed * time, so if the speeds are s and 2s, then
4(2s) = 4s + 1800
4(2s) = 4s + 1800
Related Questions
2 planes leave the airport at the same time. Minutes later plane A is 70 miles due north of the a...
Uniform Motion Related Problem
Two planes leave an airport at 2 p.m., one flying south at 450 kph,...
Two airplanes leave an airport at the same time. one travels in the direction of 38 degrees at 140mp...
An airplane flying east at 360 km/h passes over Pearson airport 10 minutes before a second airplane...