Asked by Mark

two airplanes leave an airport at the same time one hour later they are 189km/hr apart. if one plane traveled 168km/hr and the other traveled 244km/hr for the hour what is the angle between their flight path
Answered by Reiny
Did you make your sketch?
You have a triangle with all sides known, a clear case of the cosine law,
let the angle between them be Ø
189^2 = 244^2 + 168^2 - 2(244)(168)cosØ
2(244)(168)cosØ = 244^2 + 168^2 - 189^2
cosØ = (244^2 + 168^2 - 189^2)/(2(244)(168) )
take over, let me know what you got, so I can check it
Answered by Anonymous
1066
Answered by lele
no
Answered by Anonymous
the answer is 50.6
Answered by Anonymous
0.63?
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