Asked by masre man

Two planes leave an airport flying at the same rate.If the first plane flies 1.5 hours longer than the second plane and travels 2700 miles while the second plane travels only 2025 miles,
for how long was each plane flying?
Answered by masre man
rate=distance/time

2700/*=2025/y
2700/*=2025/*-1.5,
*diferent from 0,1.5

*=6hrs & y=4.5hrs
Answered by Reiny
Let their rate be x mph
time for first = 2700/x
time for second = 2025/x

2700/x - 2025/x = 1.5
times x
2700 - 2025 = 1.5x
x = 450
so the first flew for 2700/450 hrs or 6 hrs
a nd the 2nd flew for 2025/450 or 4.5 hrs

notice the difference is 1.5 hrs
Answered by masre man
Thank You! and
my answer and your answer are the same
Answered by Reiny
It is just that your text came out weird.
What's with all the * symbols all over the place?
Answered by masre man
* this symbols multiply
Answered by Reiny
yup, that's what it means.
So what is " *diferent from 0,1.5 " and " 2700/*=2025/*-1.5, " ???

That's what I was objecting to.
Answered by masre man
excuse me
* this symbols star
Answered by sosena bamlak
Yes the answer is 6hrs& 4.5hrs exact answer