Question

What is the volume of solution in which 7.6 g of FeSO4 should be dissolved in order to obtain
a solution is 0.1 N?

Answer 1

Technically the normality can't be calculated without knowing the reaction; however, in problems of this sort what USUALLY is done is divide the molar mass by the total positive or negative charge. Therefore, molar mass/2 = equivalent weight. The molar mass is approximately 152 g (you need to use a better number) so the equivalent weight will be about 152/2 = about 76 and the milliequivalent weight will be about 0.076.
mL x N x milliequivalent weight = grams
mL x 0.1 x 0.076 = 7.6
solve for mL.
Check my work.

Answer 2

Thank u very much :)