Asked by Apoorva
what volume of a 0.5M solution of sulphuric acid is required to prepare 2 litres of a 0.4M solution of the acid
Answers
Answered by
DrBob222
mL1 x M1 = mL2 x M2
mL1 x 0.5M = 2000 mL x 0.4
Solve for mL1.
mL1 x 0.5M = 2000 mL x 0.4
Solve for mL1.
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