Question
what volume of a 0.5M solution of sulphuric acid is required to prepare 2 litres of a 0.4M solution of the acid
Answers
DrBob222
mL1 x M1 = mL2 x M2
mL1 x 0.5M = 2000 mL x 0.4
Solve for mL1.
mL1 x 0.5M = 2000 mL x 0.4
Solve for mL1.