Asked by ken
What volume of hcl solution of density 1.2g/cm3 and containing 36.5% by weight hcl, must be allowed to react with zinc in order to liberate 4g of hydrogen
The answer 333.3ml
Who helps me step by step for me
The answer 333.3ml
Who helps me step by step for me
Answers
Answered by
DrBob222
What is the molarity of the HCl solution? That's
1000 mL x 1.2 g/mL x 0.0365 x (1 mol/36.5g) = 12M
Zn + 2HCl ==> ZnCl2 + H2
How many mols is 4g H2.
mol = grams/molar mass = 4/2 = 2
2 mols H2 = 2*2 = 4mols HCl
M HCl = mols HCl/L HCl. You know M HCl from above and mols HCl from above, solve for L HCl and convert to mL.
1000 mL x 1.2 g/mL x 0.0365 x (1 mol/36.5g) = 12M
Zn + 2HCl ==> ZnCl2 + H2
How many mols is 4g H2.
mol = grams/molar mass = 4/2 = 2
2 mols H2 = 2*2 = 4mols HCl
M HCl = mols HCl/L HCl. You know M HCl from above and mols HCl from above, solve for L HCl and convert to mL.
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