Asked by Help me
60 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 m lead(II) nitrate. How many grams of lead (II) iodide will precipitate?
Answers
Answered by
oobleck
2KI + Pb(NO3)2 = PbI2 + 2KNO3
You will get half as many moles of PbI2 as you use moles of KI
so now just see which gets used up first, and that will tell you how many grams are produced.
You will get half as many moles of PbI2 as you use moles of KI
so now just see which gets used up first, and that will tell you how many grams are produced.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.