Asked by jennifer
24,8% of potassium ,34,77% of Mn,40,5% of oxygen how do i find the emperical formular thanks in advance
Answers
Answered by
Jai
From the periodic table, the atomic masses of each are:
K = 39
Mn = 55
O = 16
Divide the percentage to the respective atomic mass:
K: 24.8 / 39 = 0.636
Mn: 34.77 / 55 = 0.632
O: 40.5 / 16 = 2.531
Divide each by the smallest number. The smallest number here is 0.632:
K: 0.636 / 0.632 = 1.006
Mn: 0.632 / 0.632 = 1
O: 2.531 / 0.632 4.005
Approximate each number, so that it becomes the number of atoms of that particular element in the formula. Therefore, the formula is KMnO4.
K = 39
Mn = 55
O = 16
Divide the percentage to the respective atomic mass:
K: 24.8 / 39 = 0.636
Mn: 34.77 / 55 = 0.632
O: 40.5 / 16 = 2.531
Divide each by the smallest number. The smallest number here is 0.632:
K: 0.636 / 0.632 = 1.006
Mn: 0.632 / 0.632 = 1
O: 2.531 / 0.632 4.005
Approximate each number, so that it becomes the number of atoms of that particular element in the formula. Therefore, the formula is KMnO4.
Answered by
jennifer
Thank you
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