to do what? make 0.148 M NaI in 500 mL?
How many mols do you need? That's M x L = mols.
Then mols = grams/molar mass. You have mols and molar mass, solve for grams.
solution of 0.148 M sodium iodide for an experiment in lab, using a 500 mL volumetric flask. How much solid sodium iodide should you add
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