Question
A solution of sodium cyanide NACN has a PH of 12.10. How many grams of NACN are in 425ml of solution with the same PH?
Please helps me to solve it for me
Please helps me to solve it for me
Answers
How to calculate PH 1.9 = 0.0126M Why?
How to calculate PH 1.8 = ?
How to calculate PH 20 = ?
How to calculate PH 21 = ?
Pls helps me
How to calculate PH 1.8 = ?
How to calculate PH 20 = ?
How to calculate PH 21 = ?
Pls helps me
pH = -log(H^+)
1.9 = -log(H^+)
-1.9 = log(H^+).
(H^+) = 0.01259 which rounds to 0.126
The others are done the same way.
1.9 = -log(H^+)
-1.9 = log(H^+).
(H^+) = 0.01259 which rounds to 0.126
The others are done the same way.
pH = 12.10
pH + pOH = pKw = 14
Substitute and sole for pOH. You should get 1.9 for pOH, then
pOH = -log(OH^-) and (OH^-) = 0.0126M.
0.0126M mans 0.0126 mols/L soln. For 425 mL you will have 0.0126 mol x (425/1000) = about 0.00536 mols. Then grams = mols x molar mass NaCN.
pH + pOH = pKw = 14
Substitute and sole for pOH. You should get 1.9 for pOH, then
pOH = -log(OH^-) and (OH^-) = 0.0126M.
0.0126M mans 0.0126 mols/L soln. For 425 mL you will have 0.0126 mol x (425/1000) = about 0.00536 mols. Then grams = mols x molar mass NaCN.
I do not still understand how to calculate PH 1.9 = 0.0126M
I want step by step to calculate for me.
Thank you for your help.
I want step by step to calculate for me.
Thank you for your help.
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