Asked by Mike
Solve 9⋅8^(7/x)=6
Answers
Answered by
Reiny
9⋅8^(7/x)=6
we'll need logs
8^(7/x) = 2/3
take logs of both sides, and use your log rules
(7/x)log8 = log (2/3)
7/x = (log2 - log3)/log8
x/7 = log8/(log2 - log3)
x = 7log8/(log2 - log3) = ...... button-pushing time
let me know what you get.
we'll need logs
8^(7/x) = 2/3
take logs of both sides, and use your log rules
(7/x)log8 = log (2/3)
7/x = (log2 - log3)/log8
x/7 = log8/(log2 - log3)
x = 7log8/(log2 - log3) = ...... button-pushing time
let me know what you get.
Answered by
henry2,
9.8^(7/x) = 6.
(7/x)*Log9.8 = Log6
Divide both sides by Log 9.8:
7/x = 0.785
X = 8.92.
(7/x)*Log9.8 = Log6
Divide both sides by Log 9.8:
7/x = 0.785
X = 8.92.
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