Asked by Rpeep

Find the equation of the tangent line to the curve y=6xcosx at the point (pi,-6pi)
The equation of this tangent line can be written in the form y=mx+b
What is m ?
What is b ?
Answered by oobleck
y = 6x cosx
y' = 6cosx - 6x sinx
So now evaluate m = y'(π)
The point-slope form is
y = m(x-π) - 6π
now rearrange to slope-intercept to find b.