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geoff planted dahlias in his garden. dahlias have bulbs that divide and reproduce underground. in the first year, geoff's garde...Asked by Adrianna
Geoff planted dahlias in his garden. Dahlias have bulbs that divide and reproduce underground. In the first year, Geoff’s garden produced 6 bulbs. In the second year, it produced 12 bulbs, and in the third year, it produced 24 bulbs. If this pattern continues, how many bulbs should Geoff expect in the eighth year?
A. 48 bulbs
B. 384 bulbs
C. 768 bulbs
D. 1,536 bulbs
I'm thinking it's A.
A. 48 bulbs
B. 384 bulbs
C. 768 bulbs
D. 1,536 bulbs
I'm thinking it's A.
Answers
Answered by
Damon
every year it multiplies by 2
48 would be the FOURTH year
a = 6
r = 2
https://www.mathsisfun.com/algebra/sequences-sums-geometric.html
48 would be the FOURTH year
a = 6
r = 2
https://www.mathsisfun.com/algebra/sequences-sums-geometric.html
Answered by
henry2,
Bulbs = 2^n * 3. n = the number of years.
1st year: 2^1 * 3 = 6 bulbs.
2nd year: 2^2 * 3 = 12 bulbs.
3rd year: 2^3 * 3 = 24 bulbs.
8th year: 2^8 * 3 = 768 bulbs.
1st year: 2^1 * 3 = 6 bulbs.
2nd year: 2^2 * 3 = 12 bulbs.
3rd year: 2^3 * 3 = 24 bulbs.
8th year: 2^8 * 3 = 768 bulbs.
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