Question

A train moving 60mph leaves the station at noon. An hour later, a train moving 80mph leaves leading the same direction on a parallel track. In how many hours does the second train catch up with the first?

Answer 1

distance = rate * time ... the distances are equal

80 * t = 60 * (t + 1)

80 t = 60 t + 60 ... 20 t = 60

Answer 2

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