Asked by help pls
A train leaves the station at time xequals
0.
Traveling at a constant speed, the train travels 328
km in 3.4
h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph.
0.
Traveling at a constant speed, the train travels 328
km in 3.4
h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph.
Answers
Answered by
oobleck
speed = 328km/3.4hr = 96.47 km/hr
If we round before calculating, that is 330/3 = 110 km/hr
x y
0 0
10 1100
20 2200
...
Or maybe you want to round after calculating. You're kinda vague.
If we round before calculating, that is 330/3 = 110 km/hr
x y
0 0
10 1100
20 2200
...
Or maybe you want to round after calculating. You're kinda vague.
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