Asked by luckybee
an express train leaves new york at 3:00 pm and rreaches boston at 6:00 pm a slow train leaves boston at 1:30pm and arrives in new york at 6:00 pm. if both trains travel at constant speeds at what time do they meet
Answers
Answered by
Steve
the sum of the distances traveled by each train is one trip.
Since distance = speed * time,
if x is the time traveled by the fast train,
x/3 + (x+3/2)/4.5 = 1
x = 6/5
So, in 1.2 hours, the trains meet. That is, at 4:12
Since distance = speed * time,
if x is the time traveled by the fast train,
x/3 + (x+3/2)/4.5 = 1
x = 6/5
So, in 1.2 hours, the trains meet. That is, at 4:12
Answered by
Anonymous
A train leaves Orlando at 3:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels 20 mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains?
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