Asked by Alice
at 2 pm a freight train leaves a station and travels at 42 km/h. at 11pm and express train leaves the same station on a parallel track and travels at 105 km/h in the same direction. how far from the station will they meet?
Answers
Answered by
Steve
since distance = speed 8 time, we want
42t = 105(t-9)
t = 15
So, at 5 am the next day they meet, after having gone 630km.
Or, you can consider that the freight train has a 9*42=378km head start, so the express train, traveling 63km faster, makes up the distance in 6 hours, after 630km.
42t = 105(t-9)
t = 15
So, at 5 am the next day they meet, after having gone 630km.
Or, you can consider that the freight train has a 9*42=378km head start, so the express train, traveling 63km faster, makes up the distance in 6 hours, after 630km.
Answered by
Alice
how did you get 630km
Answered by
Steve
multiply the speed by the time taken. The freight train traveled for 15 hours at 42 km/hr.
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