let the distance traveled when the second catches up
be x miles
time for the freight train to go x miles = x/35
time for the faster train to go x miles = x/60
x/35 - x/60 = 1
times 420 , the LCD
12x - 7x = 420
5x = 420
x = 84 miles
check:
time for freight to go 84 miles = 84/35 = 2.4 hrs
time for faster train to go 84 miles = 84/60 = 1.4
which is a difference of 1 hour as required.
A freight train leaves Chicago traveling West at 35 mph. An hour later a passenger train leaves Chicago traveling on a parallel track at 60 mph. How far from Chicago will the passenger train catch up to the freight train?
1 answer
1 answer