Asked by Sarah

A freight train leaves Chicago traveling West at 35 mph. An hour later a passenger train leaves Chicago traveling on a parallel track at 60 mph. How far from Chicago will the passenger train catch up to the freight train?
Answered by Reiny
let the distance traveled when the second catches up
be x miles
time for the freight train to go x miles = x/35
time for the faster train to go x miles = x/60

x/35 - x/60 = 1
times 420 , the LCD
12x - 7x = 420
5x = 420
x = 84 miles

check:
time for freight to go 84 miles = 84/35 = 2.4 hrs
time for faster train to go 84 miles = 84/60 = 1.4
which is a difference of 1 hour as required.
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