Asked by Fiyimfoluwa

A body moving at simple harmonic motion has an amplitude 50cm and a frequency of 50HZ ,find
(a) the period of oscillation
(b) the acceleration of the maximum displacement

Answers

Answered by bobpursley
Isn't period the reciprocal of frequency?
y=position- Asin(2PI*f*t)
y'=velocity=A*2pif cos..
y"=accleration=A (2piIf)^2 sin...
Answered by Damon
T = 1/f = 1/50 seconds

x = 0.50 sin w t where w = 2 pi f
v = 0.50 w cos w t
a = -0.50 w^2 sin wt = -w^2 x
maximum of sin is 1.00
so
a max = -0.50 (4 pi^2* 50^2)
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