Asked by Fiyimfoluwa
A body moving at simple harmonic motion has an amplitude 50cm and a frequency of 50HZ ,find
(a) the period of oscillation
(b) the acceleration of the maximum displacement
(a) the period of oscillation
(b) the acceleration of the maximum displacement
Answers
Answered by
bobpursley
Isn't period the reciprocal of frequency?
y=position- Asin(2PI*f*t)
y'=velocity=A*2pif cos..
y"=accleration=A (2piIf)^2 sin...
y=position- Asin(2PI*f*t)
y'=velocity=A*2pif cos..
y"=accleration=A (2piIf)^2 sin...
Answered by
Damon
T = 1/f = 1/50 seconds
x = 0.50 sin w t where w = 2 pi f
v = 0.50 w cos w t
a = -0.50 w^2 sin wt = -w^2 x
maximum of sin is 1.00
so
a max = -0.50 (4 pi^2* 50^2)
x = 0.50 sin w t where w = 2 pi f
v = 0.50 w cos w t
a = -0.50 w^2 sin wt = -w^2 x
maximum of sin is 1.00
so
a max = -0.50 (4 pi^2* 50^2)
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