Asked by Mhamad
A particle is in simple harmonic motion along the x-axis. The amplitude of the oscillation is A and its period is T. If at t = 0 the particle is at x = +A, then at t = 1.25T, the particle i
Answers
Answered by
Anonymous
we want max at t = 0 so use cosine
x =A cos (2 pi t/T)
at t = 1.25 T, same as t = 0.25 T
x = A cos(2 pi * .25) = A cos pi/2 = A * 0 = 0
x =A cos (2 pi t/T)
at t = 1.25 T, same as t = 0.25 T
x = A cos(2 pi * .25) = A cos pi/2 = A * 0 = 0
Answered by
Rami
shaklo kamin inti 3ndak assignment physics lmao
Answered by
Rami
Answer: At t=1.25T , the particle is at x=0 and is travelling toward x = -A
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