The area of a playground is 216 yd2. The width of the playground is 6 yd longer than its length. Find the length and width of the playground, including appropriate units. Then, enter the sum of the length and width in the provided grid. Show your work

please help

Answers

Answered by Damon
w (w+6) = 216
w^2 + 6 w - 216 = 0
(w-12)(w+18) = 0
w = 12, L = 18
thank you
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions