Asked by ismackyourfacewithabanana!
The area of a playground is 221 yd^2. The width of the playground is 4 yd longer than its length. Find the length and width of the playground.
Answers
Answered by
drwls
Solve w*(w-4) = 221
Width is usually less than length for a rectangle, but that is not the case here.
Try factoring
w^2 - 4w -221 = 0, and
take the positive root.
You should end up with integers for the length and the width.
w-4 is the length.
Width is usually less than length for a rectangle, but that is not the case here.
Try factoring
w^2 - 4w -221 = 0, and
take the positive root.
You should end up with integers for the length and the width.
w-4 is the length.
Answered by
ismackyourfacewithabanana!
Thank you :)!
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