Asked by Joshua
Given: Two teams of children are well-matched, and they pull on the rope with exactly the same force. They have placed a 65n weight at the center of the rope. The teams first pull with 750n of force each, then in an heroic effort to straighten the rope, pull with 1500n of force.
Find:
What is the angle of the rope makes with the horizontal with.
a. a force of 750n on each end of the rope.
b. a force of 1,500n on each end
Find:
What is the angle of the rope makes with the horizontal with.
a. a force of 750n on each end of the rope.
b. a force of 1,500n on each end
Answers
Answered by
bobpursley
Each end is supporting 1/2 the weight.
Look at the force triangle:
tanTheta=1/2 mg /tensioninRope
Look at the force triangle:
tanTheta=1/2 mg /tensioninRope
Answered by
Joshua
so it would be something like this.
a.
tan theta=1/2(65)/750
tan theta=0.043
theta=tan-1(0.043)
theta = 2.48 degree's
a.
tan theta=1/2(65)/750
tan theta=0.043
theta=tan-1(0.043)
theta = 2.48 degree's
Answered by
bobpursley
Yes, I didn't punch it in my calc.
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