Question

Four teams are playing in a tournament. Each team will play each other one more time before the top two teams play the championship game. How many games will be played?

Need some help with this mates.

Answer 1

combinations of four taken two at a time = 4C2 = 4!/[ 2! (4-2)! ]
= 4*3*2 /(2 * 2) = 6 games before the final
so 7

Answer 2

Whoops, you do not do it that way in grade 5

Make a grid
___A___B___C___D
A --- * --* --*
B----------*---*
C--------------*
D ------------- The stars are the games played in the first round
You see there are 6 of them
then the final is 7

Answer 3

That did not line up right, but I hope you see the point

Answer 4

another way
A plays the other 3
B plays only C and D more because has already played A that is 2 more
C plays only D because has played A and B so one more
3+2+1 = 6 again
plus that last game = 7

Answer 5

Thanks mate. I owe ye big time.
(I'm not in 5th grade ;P)

Answer 6

You are welcome :)

Answer 7

At the volleyball championship tournament 7 teams are registered.If each teams must play each of the other teams how many games will be played math question.

Answer 8

In analysing the words of the question the words " one more time " to me imply that these teams played each other TWICE.
Therefore the number of games played will be : 3 + 2 + 1= 6games for the first round then another 6 games return matches plus the final game making a total of 13 games.
(i.e)

2(3+2+1)+ 1(Final game )
= 2(6)+1
= 12+1
= 13 games