56 employees in an office wear glasses 32 have single vision correction and 24 wear bifocals if 2 employees are selected at random from this group what is the probability that both of them where bifocals what is the probability that both have single vision correction

Answer 1

This is just multiple selection without replacement
P(bi,bi) = 24/56 * 23/55
P(single,single) = 32/56 * 51/55

Answer 2

typo 31/55