Asked by mohamed
how do you expand double brackets?
Answers
Answered by
oobleck
give an example, or try google first.
Answered by
anonymous
to expand double brackets you use FOIL
for example
(a+4)(a+2)
for this one you get A from the first set of bracket and multiply (a+2) which becomes: a^2+2a
then you get 4 from the first set of brackets and multiply (a+2) which becomes: 4a +8 (4*2=8)
and you put a^2+2a and 4a +8 together and becomes a^2+2a+4a+8 and add 2a+4a which becomes 6a
so the final answer is a^2+6a+8
(a+4)(a+2)
=a^2+2a+4a+8
=a^2+6a+8
for example
(a+4)(a+2)
for this one you get A from the first set of bracket and multiply (a+2) which becomes: a^2+2a
then you get 4 from the first set of brackets and multiply (a+2) which becomes: 4a +8 (4*2=8)
and you put a^2+2a and 4a +8 together and becomes a^2+2a+4a+8 and add 2a+4a which becomes 6a
so the final answer is a^2+6a+8
(a+4)(a+2)
=a^2+2a+4a+8
=a^2+6a+8
Answered by
Damon
(a+4)(a+2)
when in danger or in doubt:
(a+4)(a+2)
is the same as
a (a+2) + 4(a+2)
= a^2 + 2 a + 4 a + 8
= a^2 + 6 a + 8
You do not really need that for a FOIL problem, but keep it in mind for when things get messier.
when in danger or in doubt:
(a+4)(a+2)
is the same as
a (a+2) + 4(a+2)
= a^2 + 2 a + 4 a + 8
= a^2 + 6 a + 8
You do not really need that for a FOIL problem, but keep it in mind for when things get messier.
Answered by
Damon
for distributive property see:
https://www.mathsisfun.com/definitions/distributive-law.html
https://www.mathsisfun.com/definitions/distributive-law.html