Asked by layla
what would be the rate of production for: (C6H5)CH2Cl ?
(C6H5)CH2SH ->k1 <-k-1 (C6H5)CH2+ + HS−
(C6H5)CH2+ + Cl− ->k2 (C6H5)CH2C
please help how do i solve this question?
these are the options to choose from:
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ Cl− ]+k2[ HS− ]
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ HS− ]+k2[ Cl− ]
Rate=k1 k2k−1 [ (C6H5)CH2Cl ] [ HS− ][ (C6H5)CH2SH ] [ Cl− ]
Rate=k1k−1 [ (C6H5)CH2SH ] [ Cl− ]
Rate=(k1−k−1+k2) [ (C6H5)CH2SH ] [ Cl− ]
Rate=k1 k2k−1 [ (C6H5)CH2SH ] [Cl− ]
(C6H5)CH2SH ->k1 <-k-1 (C6H5)CH2+ + HS−
(C6H5)CH2+ + Cl− ->k2 (C6H5)CH2C
please help how do i solve this question?
these are the options to choose from:
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ Cl− ]+k2[ HS− ]
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ HS− ]+k2[ Cl− ]
Rate=k1 k2k−1 [ (C6H5)CH2Cl ] [ HS− ][ (C6H5)CH2SH ] [ Cl− ]
Rate=k1k−1 [ (C6H5)CH2SH ] [ Cl− ]
Rate=(k1−k−1+k2) [ (C6H5)CH2SH ] [ Cl− ]
Rate=k1 k2k−1 [ (C6H5)CH2SH ] [Cl− ]
Answers
Answered by
kevin
i have a similar problem and i got
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ HS− ]+k2[ Cl− ]
Rate= k1 k2 [ (C6H5)CH2SH ] [ Cl− ]k−1[ HS− ]+k2[ Cl− ]
Answered by
DrBob222
I think you have made a typo (at least one). Where did the intermeddiate HS^- go? Also I expect that in the second step that is supposed to be
(C6H5)CH2CH2Cl as the final product.
(C6H5)CH2CH2Cl as the final product.
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