Asked by sarah
How many grams of CO2 are produced when 11.47 moles hexane combust?
Show work please
Show work please
Answers
Answered by
DrBob222
2C6H14 + 19O2 ==> 12CO2 + 14H2O
Use the coefficients in the balanced equation to convert mols C6H14 to mols CO2
Then convert mols CO2 to grams. g = mols x molar mass.
Use the coefficients in the balanced equation to convert mols C6H14 to mols CO2
Then convert mols CO2 to grams. g = mols x molar mass.
Answered by
Sarah
I balanced the equation like so C6H14 + 19/2 O2 ==> 6CO2 + 7H2O
My teacher taught us the 19/2 was valid
My work:
11.47 mol C6H14 * 6 CO2/1 mol C6H14 * 44g/mol/1 mol CO2 = 3, 028 g of CO2
My teacher taught us the 19/2 was valid
My work:
11.47 mol C6H14 * 6 CO2/1 mol C6H14 * 44g/mol/1 mol CO2 = 3, 028 g of CO2
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