How many grams of CO2 are produced when 11.47 moles hexane combust?
My work:I balanced the equation like so C6H14 + 19/2 O2 ==> 6CO2 + 7H2O
My teacher taught us the 19/2 was valid
My work:
11.47 mol C6H14 * 6 CO2/1 mol C6H14 * 44g/mol/1 mol CO2 = 3, 028 g of CO2
9 years ago
9 years ago
Agreed. In high school I was taught something else. Like multiply every thing by 2. To get a whole number.
Thank you for your help
11 months ago
To find the number of grams of CO2 produced when 11.47 moles of hexane (C6H14) combusts, you need to use the balanced equation for the combustion reaction:
C6H14 + 19/2 O2 → 6 CO2 + 7 H2O
Based on the balanced equation, 1 mole of hexane (C6H14) produces 6 moles of carbon dioxide (CO2).
To start, convert moles of hexane to moles of carbon dioxide using a conversion factor:
11.47 mol C6H14 * 6 mol CO2 / 1 mol C6H14 = 68.82 mol CO2
Next, convert moles of carbon dioxide to grams of carbon dioxide using the molar mass of CO2:
68.82 mol CO2 * 44 g/mol = 3,028 g CO2
Therefore, when 11.47 moles of hexane combusts, approximately 3,028 grams of carbon dioxide are produced.