Question

How do I go about integrating sin[x^(1/3)]dx?? I tried doing integration by parts and I'm going in circles.

Answer 1

let x^(1/3) = w
w^3 = x
dx = 3w^2 dw
The integral becomes
3 *INTEGRAL w^2 sin w dw
The integral of that is in my table of integrals and it looks like you need to apply integration by parts twice to get it.

Answer 2

I GOT IT! Thank you so so much for guiding me in the right direction!!

Answer 3

I'm sure glad you had the satisfaction of solving it; I was just too lazy to do the whole thing.