Asked by Anonymous
Find the integrating factor for the following differential equation
(cos8x)y′+8(tan8x)y=4sec8x,0<x<π/16.
(cos8x)y′+8(tan8x)y=4sec8x,0<x<π/16.
Answers
Answered by
Steve
cos8x y' + 8tan8x y = 4sec8x
as you recall, the IF for
y' + py = q is e^(∫p dx)
Now, if you put your equation into that form, you have
y' + 8(sec8x)(tan8x)y = 4sec^2(8x)
That should look fairly familiar, as far as integrals go.
as you recall, the IF for
y' + py = q is e^(∫p dx)
Now, if you put your equation into that form, you have
y' + 8(sec8x)(tan8x)y = 4sec^2(8x)
That should look fairly familiar, as far as integrals go.
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