Asked by Kimbery
The vertices of triangle ABC are A(-5, 2), B(-2, 5), and C(3, 4). Write an equation in slope-intercept form for the line containing the median of triangle ABC through point B.
Can someone please help me figure out how to solve this equation?
Can someone please help me figure out how to solve this equation?
Answers
Answered by
Damon
Sure
one point on your line is point B (-2 , 5)
the other is the midpoint of AC
average x = (-5+3)/2 = -1
average y = (2+4)/2 = 3
so second point is (-1 , 3)
now I bet you know how to find the equation of the line through
(-2 , 5) and (-1 , 3)
one point on your line is point B (-2 , 5)
the other is the midpoint of AC
average x = (-5+3)/2 = -1
average y = (2+4)/2 = 3
so second point is (-1 , 3)
now I bet you know how to find the equation of the line through
(-2 , 5) and (-1 , 3)
Answered by
Ms Pi 3.14159265358979323
The median is located in the middle of A to C.
Use your midpoint formula to locate it (remember the midpoint is adding up the ((x1 + x2)/2, (y1 + y2)/2)
So the x co-ordinate of the median is (-5 +3)/2
That is -2/2,
which is 1
(1, y)
You find y.
Then use the B coordinate and your median point (that is 2 points and you find the equation of that line : )
Use your midpoint formula to locate it (remember the midpoint is adding up the ((x1 + x2)/2, (y1 + y2)/2)
So the x co-ordinate of the median is (-5 +3)/2
That is -2/2,
which is 1
(1, y)
You find y.
Then use the B coordinate and your median point (that is 2 points and you find the equation of that line : )
Answered by
Damon
Ms Pi typo, means -2/2 is -1