Asked by AAA
A closed surface is constructed in the space between two large parallel metal plates, where there is a constant electric field E. The magnitude of the field is |E| = 1880 N/C. The numbers (1), (2), and (3) in the simulation label small increments of area of 1.1 cm^2 on the surface. The direction of each increment is defined to be the direction of a vector out of the surface and perpendicular to the increment's surface area. With that definition assume the direction of the first increment ΔA1 is 65° from the direction of E, that the second increment ΔA2 is oriented 90° from the direction of E, and that the third increment ΔA3 is oriented 135° from the direction of E. Find the flux through each of the three increments of area
Answers
Answered by
AAA
I use the formula Phi=EAcos(θ)
For ΔA1 I got 1880(.00011m^2)cos(65)=.05486N*m^2/C but this is not the answer. Can somebody show how to get to the answer key .0874N*m^2/C? Once I know how I will do the rest for the 2 and 3
For ΔA1 I got 1880(.00011m^2)cos(65)=.05486N*m^2/C but this is not the answer. Can somebody show how to get to the answer key .0874N*m^2/C? Once I know how I will do the rest for the 2 and 3
Answered by
Damon
angle wrong, 65 to normal is 25 to surface. zero would be flat against your hot plate 90 - 65 = 25
1880(.00011m^2)cos(25) = 0.1874 not 0.0874
1880(.00011m^2)cos(25) = 0.1874 not 0.0874
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.